Hello Q-Chem Community,
I need to study the S1 state of benzene when the symmetry is broken. This is needed for PES calculation.
First I made some test when the symmetry is on, it uses D2h group, so S1 is described by B2u representation, [0,0,0,0,0,0,1,0], the excitation value is 4.8634 eV. When I turn off symmetry, then the lowest excitation energy is 6.3832 eV while I expected 4.8634 eV.
I tried to do the same test in Molpro and it worked. What am I doing wrong?
The inputs are below.
With symmetry
$molecule
0 1
H 4.739433138 0.000000000 0.000000000
H -4.739433138 0.000000000 0.000000000
H 2.369716569 4.104470040 0.000000000
H -2.369716569 4.104470040 0.000000000
H -2.369716569 -4.104470040 0.000000000
H 2.369716569 -4.104470040 0.000000000
C 2.704198094 0.000000000 0.000000000
C -2.704198094 0.000000000 0.000000000
C 1.352099047 2.341903580 0.000000000
C -1.352099047 2.341903580 0.000000000
C -1.352099047 -2.341903580 0.000000000
C 1.352099047 -2.341903580 0.000000000
$end
$rem
INPUT_BOHR TRUE
METHOD eom-ccsd
BASIS aug-cc-pvdz
EE_STATES [0,0,0,0,0,0,2,0]
$end
Without symmetry, the molecule block is the same
$rem
INPUT_BOHR TRUE
SYMMETRY FALSE
CC_SYMMETRY FALSE
METHOD eom-ccsd
BASIS aug-cc-pvdz
EE_STATES [2]
$end
P.S. I am using the 5.1 version